The real roots of the equation $x^{2} + 5 | x | + 4 = 0$ are

(- 1, - 4)

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(1, 4)

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(- 4, 4)

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No real root

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Solution

The correct option is D No real root
Given equation
$x^{2} + 5 | x | + 4 = 0$
$\Rightarrow | x |^{2} + 5 | x | + 4 = 0$
Put $| x | = t$
$\Rightarrow t^{2} + 5 t + 4 = 0$
$\Rightarrow (t + 1) (t + 4) = 0$
$\Rightarrow t = - 1, - 4$
$| x | = - 1, | x | = - 4$
Both are not possible .
Hence, no real roots .

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The real roots of the equation x2+5|x|+4=0 are

The correct option is D No real rootGiven equationx2+5|x|+4=0⇒|x|2+5|x|+4=0Put |x|=t⇒t2+5t+4=0⇒(t+1)(t+4)=0⇒t=−1,−4|x|=−1,|x|=−4Both are not possible .Hence, no real roots .

The real roots of the equation $x^{2} + 5 | x | + 4 = 0$ are