The recommended concentration of fluoride ion in drinking water is up to 1 ppm as fluoride ion is by converting $[3 C a_{3} (P O_{4})_{2} . C a (O H)_{2}]$ to:

[3 C a_{3} (P O_{4})_{2} . C a F_{2}]

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[3 C a_{3} (O H)_{2} . C a F_{2}]

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[C a F_{2}]

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[3 (C a F_{2}) . C a (O H)_{2}]

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Solution

The correct option is A $[3 C a_{3} (P O_{4})_{2} . C a F_{2}]$
The Fluoride ion converts $[3 C a_{3} (P O_{4})_{2} . C a (O H)_{2}]$ to $[3 C a_{3} (P O_{4})_{2} . C a F_{2}]$ .

The reaction can be given as follow:

$[3 C a_{3} (P O_{4})_{2} . C a (O H)_{2}] drinking water upto 1 ppm + 2 F^{-} \to [3 C a_{3} (P O_{4})_{2} . C a F_{2}] harder teeth enamel$

Hence, the correct option is $A$

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Similar questions

[3 C a_{3} (P O_{4})_{2} . C a (O H)_{2}]

[3 C a_{3} (P O_{4})_{2} . C a (O H)_{2}]

C a F_{2}

4.1 \times 10^{- 4} M

K_{s p}

C a F_{2}

F^{-}

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