The relation among u, v and f for a mirror is

f = u v / (u + v)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

v = f u / (u + f)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

u = f v / (f + v)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

All of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $f = u v / (u + v)$
According to mirror equation.
$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$
$\frac{1}{f} = \frac{u + v}{u v}$
$f = \frac{u v}{u + v}$

Similarly,
$v = \frac{f u}{u - f}$
$u = \frac{f v}{v - f}$

Suggest Corrections

Similar questions

Q. The relation among

u

v

and

f

for a mirror is:

Q. According to lens formula, the focal length (f) of a lens is given by:
Object distance:

u

Image distance:

v

Q. By a change of variable

x (u, v) = u v, y (u, v) = v / u

in double integral, the integrand

f (x, y)

changes to

f (u v, v / u) ϕ (u, v)

. Then,

ϕ (u, v)

The focal length f of a mirror is given by $\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$ where u and v represent object and image distances respectively. The fractional error in 'f' is given by

Q. The relation between

u, v

( u is the object distance and v is the image distance ) and f for mirror is given by:

Join BYJU'S Learning Program

The relation among u, v and f for a mirror is

The correct option is A f=uv/(u+v)According to mirror equation.1f=1u+1v1f=u+vuvf=uvu+vSimilarly,v=fuu−fu=fvv−f

The correct option is A $f = u v / (u + v)$
According to mirror equation.
$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$
$\frac{1}{f} = \frac{u + v}{u v}$
$f = \frac{u v}{u + v}$

Similarly,
$v = \frac{f u}{u - f}$
$u = \frac{f v}{v - f}$