The relation R is defined on the set of natural numbers as {(a,b) : a = 2b}. Then $R^{- 1}$ is given by

{(2, 1), (4, 2), (6, 3).....}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{(1, 2), (2, 4), (3, 6)....}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
{(1, 2), (2, 4), (3, 6)....}

R = {(2,1),(4,2),(6,3),.....}.

So, $R^{- 1}$ = {(1,2),(2,4),(3,6),......}.

Suggest Corrections

Similar questions

R

N

R = {(x, y) : y = x + 5 a n d x < 4}

The relation R is defined on the set of natural numbers as {(a,b) : a = 2b}. Then $R^{- 1}$ is given by

The relation R is defined on the set of natural numbers as $\{(a, b) : a = 2 b\}$ . Then $R^{- 1}$ is given by

R

{1, 2, 3, 4, 5, 6}

R = {(a, b) : b = a + 1}

The relation R is defined on the set of natural numbers as {(a,b) : a = 2b}. Then $R^{- 1}$ is given by

Join BYJU'S Learning Program