The relative lewis acid character of boron trihalides is the order:

B I_{3} > B B r_{3} > B F_{3} > B C l_{3}

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B I_{3} > B B r_{3} > B C l_{3} > B F_{3}

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B F_{3} > B C l_{3} > B B r_{3} > B I_{3}

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B C l_{3} > B F_{3} > B I_{3} > B B r_{3}

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Solution

The correct option is A $B I_{3} > B B r_{3} > B C l_{3} > B F_{3}$
$B I_{3} > B B r_{3} > B C l_{3} > B F_{3}$

This order can be easily explained on the basis of the tendency of the halogen atom to back donate its lone pair of electrons to empty p-orbital of the boron atom through $p π - p π$ bonding.

Hence, the correct option is $B$ .

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Similar questions

The correct order of Lewis acidity of $B X_{3}$ molecule is

B F_{3} < B C l_{3} < B B r_{3} < B I_{3}

B F_{3}, B C l_{3}, B B r_{3}, B I_{3}

B F_{3}

B C l_{3}

B B r_{3}

B I_{3}

B B r_{3}, B C l_{3}

B F_{3}

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