The resistance of a bulb filament is 100 $Ω$ at a temperature of 100 $^{0}$ C. If its temperature coefficient of resistance be 0.005 per $^{0}$ C , its resistance will become 200 $Ω$ at a temperature of :

300

^{0}

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400

^{0}

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500

^{0}

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200

^{0}

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Solution

The correct option is A 300 $^{0}$ C
Given $R_{0} = 100 Ω a t 100^{0} c .$
$α = 0.005; R = 200 Ω a t T = ?$
$\Rightarrow (R - R_{0}) = R_{0} α (T - T_{0})$
$\Rightarrow 100 = 100 \times \frac{5}{1000} (T - T_{0})$
$\Rightarrow T = 200 + T_{0} = 300^{0} c$

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The resistance of a bulb filament is 100Ω at a temperature of 1000C. If its temperature coefficient of resistance be 0.005 per 0C , its resistance will become 200Ω at a temperature of :

The correct option is A 3000CGiven R0=100 Ω at 1000c. α=0.005;R=200 Ω at T=? ⇒(R−R0)=R0α(T−T0) ⇒100=100×51000(T−T0) ⇒T=200+T0=3000c

The resistance of a bulb filament is 100 $Ω$ at a temperature of 100 $^{0}$ C. If its temperature coefficient of resistance be 0.005 per $^{0}$ C , its resistance will become 200 $Ω$ at a temperature of :

The correct option is A 300 $^{0}$ C
Given $R_{0} = 100 Ω a t 100^{0} c .$
$α = 0.005; R = 200 Ω a t T = ?$
$\Rightarrow (R - R_{0}) = R_{0} α (T - T_{0})$
$\Rightarrow 100 = 100 \times \frac{5}{1000} (T - T_{0})$
$\Rightarrow T = 200 + T_{0} = 300^{0} c$