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Question

The resistance of a galvanometer is 199 . The sensitiveness is 2×104 A per division. The scale contains 100 divisions. In order to convert it into an ammeter to read upto 4 A, the shunt resistance is

A
0.5
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B
1
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C
2
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D
3.5
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Solution

The correct option is B 1
ig for one division =2×104A

S=igG(iig)

So ig for 100 divisions =2×104×100A
=2×102A
S=igG(iig)

=2×102×19942×102

=1 ohm

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