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Question

The resistance of a solution A is 50 ohms and that of solution B is 100 ohms, both solutions being taken in the same conductivity cell. If equal volumes of solution A and B are mixed, the resistance (in ohms) of the mixture using the same cell will be 13x+2. Then x is:
Assume that there is no increase in the degree of dissociation of A and B on mixing.
(write the value to the nearest integer)

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Solution

Let K1 and K2 represent the conductivities of two solutions A and B respectively.
Let x be the cell constant.
For solution A,
The conductivity is the product of the conductance and the cell constant.
K1=x50......(1)
For solution B
K2=x100......(2)
Equal volumes of A and B are mixed. Both the solutions are doubly diluted.
Their individual contribution towards the conductivity of the mixture will be K12 and K22 respectively and the conductivity of the mixture will be K1+K22
For the mixture,
K1+K22=xR......(3).
Here, R is the resistance of the mixture.
Solving equations (1), (2) and (3), we get
R=66.6767 ohm.
Hence, x=5

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