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Potentiometer

The resistivi...

Question

The resistivity of a potentiometer wire is $ρ$ and the area of cross section of the wire is $A$ . If the current flowing in the circuit is $I$ , then potential gradient will be

I A

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I A / ρ

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I ρ / A

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I A ρ

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Solution

The correct option is C $I ρ / A$
Potential Gradient $= v o l t / u n i t l e n g t h$
$= I R / l (R = ρ \frac{l}{A})$
$= \frac{I ρ}{A} (ρ = r e s i s t i v i t y)$

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