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EMF and EMF Devices

The resistor ...

Question

The resistor of resistance $R$ is connected between the terminals of a cell of emf $E$ and internal resistance $r$ . The current $I$ through the circuit is :

\frac{E}{R r}

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\frac{E}{R + r}

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\frac{R + r}{E}

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\frac{E}{R} + r

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Solution

The correct option is B $\frac{E}{R + r}$
Total resistance: R + r

By Ohm's Law,

$I = \frac{E}{R + r}$

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