Question

# The root of a quadratic equation are 5 and −2. Then, the equation is (a) ${x}^{2}-3x+10=0$ (b) ${x}^{2}-3x-10=0$ (c) ${x}^{2}+3x-10=0$ (d) ${x}^{2}+3x+10=0$

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Solution

## (b) ${x}^{2}-3x-10=0$ $\text{It is given that the roots of the quadratic equation are 5 and}-2.\phantom{\rule{0ex}{0ex}}\text{Then, the equation is:}\phantom{\rule{0ex}{0ex}}{x}^{2}-\left(5-2\right)x+5×\left(-2\right)=0\phantom{\rule{0ex}{0ex}}\text{⇒}{x}^{2}-3x-10=0\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}$

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