The root of a quadratic equation are 5 and −2. Then, the equation is
(a) $x^{2} - 3 x + 10 = 0$
(b) $x^{2} - 3 x - 10 = 0$
(c) $x^{2} + 3 x - 10 = 0$
(d) $x^{2} + 3 x + 10 = 0$

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Solution

(b) $x^{2} - 3 x - 10 = 0$

$It is given that the roots of the quadratic equation are 5 and - 2 . Then, the equation is: x^{2} - (5 - 2) x + 5 \times (- 2) = 0 ⇒ x^{2} - 3 x - 10 = 0$

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