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Question

The roots of the equation a(x2+1)āˆ’(a2+1)x = 0 are


A

a,1a

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B

a, 2a

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C

a,12a

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D

- a , -2a

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Solution

The correct option is A

a,1a


Equation a(x2+1)(a2+1)x = 0

ax2(a2+1)x+a = 0

(ax1)(xa) = 0 ⇒ x=a,1a


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