CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The roots of the quadratic equation ax2+x+b=0 are real for all values of x. If a, 1, b are in an arithmetic progression, where a,bR+, then which of the following can be the possible value of ab?
  1. 12
  2. 10
  3. 13
  4. 14


Solution

The correct option is D 14
a, 1, b are in arithmetic progression.
a+b=2

Now, the roots of the quadratic equation ax2+x+b=0 are real
(1)24ab0(a+b2)24ab0a2+b214ab0(ab)214(ab)+10(ab7)248ab(0,743][7+43,)

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image