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Question

The roster form of the set A={x:x=n2n+1, nN and n<4} is ___. (Here, N stands for the set of natural numbers)


A

A={13,25,37}

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B

A={12,23,35}

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C

A={13,15,17}

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D

A={23,25,27}

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Solution

The correct option is A

A={13,25,37}


Given, nN, n<4 and x=n2n+1.
where N stands for the set of natural numbers.

So, n=1,2,3.

Substituting n=1,2,3 in x=n2n+1, we get

x=12(1)+1=13,

x=22(2)+1=25 and

x=32(3)+1=37.

A={13,25,37}


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