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Question

The rusting of iron takes place as follows : 2H++2e+12O2H2O(l);Eo=+1.23V

Fe2++2eFe(s);Eo=0.44V

ΔGo for the net process is:

A
322 kJ mol1
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B
161 kJ mol1
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C
152 kJ mol1
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D
76 kJ mol1
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