CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The self inductance of a choke coil is mH. when it is connected with a 10 VDC source then the loss of power is 20 watt. When it connected with 10 volt AC source loss of power is 10 watt. The frequency of AC source will bw-

A
50 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
60 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
80 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
100 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 50 Hz
WhendcispassthroughtheinductornoinduvtanceeffectwillbetheironlyresistancewillbetheirresistanceoftheinductorbeR20=100RR=5ΩXl=ω×0.001power=v2zcosϕZ=25+ω2×106cosϕ=RZ=5Z10=100Z5Z=500Z2=50025+ω2×10625+ω2×106=50ω2=25×106ω=5000
=50Hz
Hence, Option A is correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Self and Mutual Inductance
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon