The set (A∪B′)′∪(B∩C) is equal to
A′∪B∩C
A′∪B
A′∪C
A′∩B
We know that,
(A∪B)′=(A′∪B′)and(A′)′=A
∴=(A∩B′)′∪(B∩C)
=[(A′∪B′)′]∪(B∩C)
= (A′∪B)∪(B∩C)=A′∪B