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Definition of Functions

The set of so...

Question

The set of solutions satisfying both $x^{2} + 5 x + 6 \geq 0 a n d x^{2} + 3 x - 4 < 0 i s$

A

$(- 4, 1)$

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B

$(- 4, - 3] \cup [- 2, 1)$

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C

$(- 4, - 3) \cup (- 2, 1)$

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D

$[- 4, - 3] \cup [- 2, 1]$

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Solution

The correct option is B
$(- 4, - 3] \cup [- 2, 1)$

$x^{2} + 5 x + 6 \geq 0 \Rightarrow x \leq - 3 o r x \geq - 2$
$x^{2} + 3 x - 4 < 0 \Rightarrow - 4 < x < 1$
$\Rightarrow x ϵ (- 4, - 3] \cup [- 2, 1)$

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Similar questions

The set of solutions satisfying both $x^{2} + 5 x + 6 \geq 0 a n d x^{2} + 3 x - 4 < 0 i s$

Q. Find the values of

x

satisfying the equation

∣ ∣ x^{2} - 9 ∣ ∣ + ∣ ∣ x^{2} - 1 ∣ ∣ + ∣ ∣ x^{2} - 5 x + 6 ∣ ∣ = 0

Q. The common root of

x^{2} - 3 x + 2

x^{2} - 5 x + 6 = 0

Q. Find the values of 'x' which satisfy

x^{2} - 3 x + 2 > 0

x^{2} - 3 x - 4 \leq 0

.

Q. Match the elements of the list I, which contains inequalities, with the elements of list II, which has solution sets.

List-I (Inequality)	List-II (Solution set)
A) $x^{2} - 4 x + 3 > 0$	1) $(3, 4)$
B) $x^{2} - 5 x + 6 \leq 0$	2) $(- 1, 1) \cup (2, 4)$
C) $x^{2} + 6 x - 27 > 0, - x^{2} + 3 x + 4 > 0$	3) $(- \infty, 1) \cup (3, \infty)$
D) $x^{2} - 3 x - 4 < 0, x^{2} - 3 x + 2 > 0$	4) $[3, 4]$
	5) $[2, 3]$

Then the correct order for A B C D, is

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