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Question

The set of values of a for which the equation acosx2sinx=2+2a possesses a solution, is

A
[15,1+5]
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B
[51,2]
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C
R
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D
(,15)
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Solution

The correct option is B [51,2]
Clearly, a0 and 2a0
0a2 (1)
Now, for solution to exist,
2+2aa+42+2a+222aa+422aa2(2a)a2a2+2a40
a15 or a1+5 (2)
From (1) and (2),
51a2

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