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Question

The set of values of a for which the point(a1,a+1) lies outside the circle x2+y2=8 and inside the circle x2+y212x+12y62=0 is

A
(32,3)(3,32)
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B
(22,3)(3,32)
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C
(32,3)(3,32)
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D
(32,3)(3,32)
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Solution

The correct option is A (32,3)(3,32)
Point (a1,a+1) lies outside the circle x2+y2=8
(a1)2+(a+1)28>0a23>0a(,3)(3.) (1)

Point (a1,a+1) lies inside the circle (x6)2+(y+6)2134=0
(a7)2+(a+7)2134<0
a218<0
a(32,32) (2)

From (1) and (2)

a(32,3)(3,32)

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