Question

The shape of $\left[Cu\right(N{H}_3{)}_4{]}^{2+}$ is square planar, $C{u}^{2+}$ in this complex is

• A. $s{p}^3$ hybridised
• B. $ds{p}^2$ hybridised
• C. $s{p}^{3}d$ hybridised
• D. $s{p}^3{d}^2$ hybridised

Answer 1

Answer: (B)

$ds{p}^2$ hybridised

Square planar geometry arises due to $ds{p}^2$ hybridisation.

$C{u}^{2+}$ ion has the electronic configuration $\left[Ar\right]3d^{9}4s^0$ and the electrons are reaaranged to $\left[Ar\right]3d^{8}4s^{0}4p^1$ and one 3d, one 4s and two 4p undergo $ds{p}^2$ hybridization and accept one lone pair of electrons each from 4 ammonia molecules.