Question

# The shape of $$XeF_4$$ is:

A
tetrahedral
B
octahedral
C
square planar
D
pyramidal

Solution

## The correct option is A square planarThe shape of $$XeF_4$$ is square planar. The central $$Xe$$ atom has 4 bond pairs of electrons and two lone pairs of electrons. It undergoes $$sp^3d^2$$ hybridization which results in octahedral electron geometry and square planar molecular geometry. The two lone pairs are at opposite corners of an octahedron. This minimizes repulsion between them.Chemistry

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