The sides of a hexagon are produced in order. If the measures of exterior angles so obtained are (6x−1)o, (10x+2)o, (8x+2)o (9x−3)o, (5x+4)o and (12x+6)o; find each exterior angle.
Sum of exterior angles of hexagon formed by producing sides of order = 360o
∴(6x−1)o+(10x+2)o+(8x+2)o+(9x−3)o+(5x+4)o+(12x+6)o=360o50x+10o=360o50x=360o−10o50x=350ox=35050x=7∴Angles are(6x−1)o; (10x+2)o;(8x+2)o; (9x−3)o; (5x+4)o and (12x+6)oi.e.,(6×7−1)o; (10×7+2)o; (8×7+2)o; (9×7−3)o; (5×7+4)o; (12×7+6)oi.e. 41o; 72o,58o; 60o;39o and 90o.