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Question

The sides of a quadrilateral ABCD are 6 cm, 8 cm, 12 cm and 14 cm (taken in order) respectively and the angle between the first two sides is a right angle. Find its area.


A
18+242 cm2
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B
18+246 cm2
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C
36+242 cm2
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D
36+246 cm2
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Solution

The correct option is A 18+246 cm2

Area of ABC=12×base×height
=12×6×8
=24cm2

Diagonal AC = BC2+AB2=10 cm

For ACD,
s=10+12+142=18
Area =s(sa)(sb)(sc)
=18(1810)(1812)(1814)
=18×8×6×4
=246 cm2

area of quadrilateral 
=18+246 cm2

Mathematics

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