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Question

The sides of a triangle of area 403 sq.cm are 10 , 6+x , 4+x . Find x


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Solution

We know that area of traingle = s(sa)(sb)(sc)

Here , s =  a+b+c2 = 10 + x

403 =  (10+x)(6)(4)(x)

Squaring on both sides ,

x2 + 10 x - 200 = 0 

Solving we get x = 10 , -20 

Since x cannot be negative , x = 10 


Mathematics

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