Solution:
Let’s assume the triangle similar to ΔABC to be ΔXYZ.
Given that the ratio of corresponding sides is 2.
So, XYAB=YZBC=XZAC=2
The sides of ΔABC are 6 cm, 8 cm and 10 cm.
Hence,
⇒XY6=YZ8=XZ10=2 [1 mark]
⇒XY=12 cm,YZ=16 cm and XZ=20 cm.
The perimeter of ΔXYZ is XY+YZ+XZ=12+16+20=48 [1 mark]