The sides of -ABC are AB - 6cm- BC - 8cm and CA -10cm- Find the perimeter of the larger triangle -XYZ which is similar to -ABC- if the ratio of their corresponding sides is 2- 2 mark

Given: Triangle ΔABC is similar to to be ΔXYZ. The ratio of corresponding sides is 2. So, XY/AB=YZ/BC=XZ/AC=2 nbsp; ⇒XY/6=YZ/8=XZ/10=2 nbsp; nbsp; nbs ...

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Standard VIII

Mathematics

Similar Triangles

The sides of ...

Question

The sides of $Δ ABC$ are AB = 6cm, BC = 8cm and CA =10cm. Find the perimeter of the larger triangle $Δ XYZ$ which is similar to $Δ ABC$ , if the ratio of their corresponding sides is 2. (2 mark)

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Solution

Given: Triangle $Δ ABC$ is similar to to be $Δ XYZ$ .
The ratio of corresponding sides is 2.
So, $\frac{X Y}{A B} = \frac{Y Z}{B C} = \frac{X Z}{A C} = 2$
$\Rightarrow \frac{X Y}{6} = \frac{Y Z}{8} = \frac{X Z}{10} = 2$ (1 mark)
$\Rightarrow$ XY = 12cm, YZ = 16cm and XZ = 20cm.
The perimeter of $Δ XYZ$ is XY + YZ + XZ = 12 + 16 + 20 = 48cm. (1 mark)

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The sides of ΔABC are AB = 6cm, BC = 8cm and CA =10cm. Find the perimeter of the larger triangle ΔXYZ which is similar to ΔABC, if the ratio of their corresponding sides is 2. (2 mark)

Given: Triangle ΔABC is similar to to be ΔXYZ. The ratio of corresponding sides is 2. So, XYAB=YZBC=XZAC=2 ⇒XY6=YZ8=XZ10=2 (1 mark) ⇒ XY = 12cm, YZ = 16cm and XZ = 20cm. The perimeter of ΔXYZ is XY + YZ + XZ = 12 + 16 + 20 = 48cm. (1 mark)

The sides of $Δ ABC$ are AB = 6cm, BC = 8cm and CA =10cm. Find the perimeter of the larger triangle $Δ XYZ$ which is similar to $Δ ABC$ , if the ratio of their corresponding sides is 2. (2 mark)