The sides of triangle are $x, x + 1, x + 2$ , if the perimeter is $24$ , find $x$ .

Open in App

Solution

The sides of triangle are $x, x + 1, x + 2$

The perimeter is sum of them
so,
$x + x + 1 + x + 2 = 24 3 x + 3 = 24 3 x = 21 x = 7$

Suggest Corrections

Similar questions

6, 7, x

18

x

The sides of a triangle are 3x+1,4x+2 & 5x. Find the perimeter of the triangle

The perimeter of a triangle is $15 x^{2} - 23 x + 9$ and two of its sides are $5 x^{2} + 8 x - 1$ and $6 x^{2} - 9 x + 4.$ Find the third side.

The perimeter of a triangle is 56m. Its sides are 2x,2x+3 and 2x+5.Find the respective length of sides of triangle.

A B C

70

x, 4 x, 5 x

x

Join BYJU'S Learning Program