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Question

The slope of the tangent at (π4,0) to the curve 1+16x2y=tan(x2y) is 
  1. 1π+4
  2. 2π+2
  3. 2π2+4
  4. 1π2+4


Solution

The correct option is C 2π2+4
Consider, 
1+16x2y=tan(x2y)
32xy+16x2y=sec2(x2y)(12y)
y=dydx
Putting (π4,0)
0+π2y=2(12y)dydx=y=2π2+4

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