CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The smallest division on the main scale of a Vernier calipers is 0.1 cm. Ten divisions of the Vernier scale correspond to nine divisions of the main scale. The figure below on the left shows the reading of this calipers with no gap between its two jaws. The figure on the right shows the reading with a solid sphere held between the jaws. The correct diameter of the sphere is

A
3.07 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.15 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3.17 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3.11 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3.15 cm
So, we have given,
10 VSD=9 MSD 1 VSD=910 MSD
Least count =1 MSD1 VSD=(1910) MSD
0.1 MSD=0.1×0.1=0.01 cm
As 0 of vernier scale lies before 0 of the main scale,
Zero error =(106)×(Least Count)=4×0.01=0.04 cm
Reading =3.1+1×(Least count)=3.1+1×0.01=3.11 cm
Therefore, true diameter =ReadingZero error
=3.11(0.04)=3.15 cm

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vernier calipers
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon