Question

The smallest ketone and its next homologue are reacted with $N{H}_{2}OH$ to form:

• A. two different oxime
• B. four different oxime
• C. three different oxime
• D. optically active oxime

Answer 1

The correct option is C three different oxime

The lowest molecular weight ketone is $Me-CO-Me$ and its nest homologue is $MeC{H}_2-CO-Me$

Therefore, correct option is $C$.