The solubility of lithium sodium hexafluoroaluminate, ${L i}_{3} {N a}_{3} {(A l F_{6})}_{2}$ is $a$ $m o l$ ${l i t r e}^{- 1}$ . Its solubility product is equal to:

s^{8}

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12 s^{3}

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18 s^{3}

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2916 s^{8}

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Solution

The correct option is C $2916 s^{8}$
$L i_{3} N a_{3} (A l F_{6})_{2} \to 3 L i^{+} + 3 N a^{+} + 2 A l F_{6}^{- 3}$
3s 3s 2s

$K_{s p} = {(3 s)}^{3} \times {(3 s)}^{3} \times {(2 s)}^{2} = 2916 s^{8}$

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Similar questions

Q. If the solubility of lithium sodium hexafluoro aluminate

{L i}_{3} {N a}_{3} {(A l F_{6})}_{2}

is 'S' moles/litre. Its solubility product is equal to:

Q. If the solubility of lithium sodium hexafluoro aluminate,

{L i}_{3} {N a}_{3} {(A l F_{6})}_{2}

S

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If the solubility of lithium sodium hexafluoroaluminate, $L i_{3} N a_{3} (A l F_{6})_{2}$ is 's' $m o l L^{- 1}$ , its solubility product is equal to -

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{L i}_{3} {N a}_{3} {({A I F}_{6})}_{2}

is 'S' moles/litre. Its solubility product is equal to:

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{L i}_{3} {N a}_{3} {(A l F_{6})}_{2}

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The solubility of lithium sodium hexafluoroaluminate, Li3Na3(AlF6)2 is a mol litre−1. Its solubility product is equal to:

The correct option is C 2916s8Li3Na3(AlF6)2→3Li++3Na++2AlF−36 3s 3s 2sKsp=(3s)3×(3s)3×(2s)2=2916s8

The solubility of lithium sodium hexafluoroaluminate, ${L i}_{3} {N a}_{3} {(A l F_{6})}_{2}$ is $a$ $m o l$ ${l i t r e}^{- 1}$ . Its solubility product is equal to:

The correct option is C $2916 s^{8}$
$L i_{3} N a_{3} (A l F_{6})_{2} \to 3 L i^{+} + 3 N a^{+} + 2 A l F_{6}^{- 3}$
3s 3s 2s

$K_{s p} = {(3 s)}^{3} \times {(3 s)}^{3} \times {(2 s)}^{2} = 2916 s^{8}$