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Solubility Product

The solubilit...

Question

The solubility product of three sparingly soluble salts $M_{2} X, M X$ and $M X_{3}$ are identical. What will be the order of their solubilities?

A

M X_{3} > M_{2} X > M X

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B

M X_{3} > M X > M_{2} X

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C

M X > M_{2} X > M X_{3}

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D

M X > M X_{3} > M X_{2}

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Solution

The correct option is A $M X_{3} > M_{2} X > M X$
Let S be the solubility in moles/ litre.

The expression for the solubility product of $M_{2} X$ is $(2 S)^{2} S = 4 S^{3}$

The expression for the solubility product of $M X$ is $S (S) = S^{2}$

The expression for the solubility product of $M X_{3}$ is $S (3 S)^{3} = 27 S^{4}$

Since solubility constant of all are same, so order of solubility
$M X_{3}$ > $M_{2} X > M X$

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Q. Solubility product constant

(K_{s p})

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4.0 \times 10^{- 8}, 3.2 \times 10^{- 14}

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