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Question

The solution for the differential equation dyy+dxx=0 is

A
1y+1x=c
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B
logx.logy=c
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C
xy=c
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D
x+y=c
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Solution

The correct option is C xy=c
dyy+dxx=0
dyy=dxx
Integrating both sides, we get
logy=logx+logc, where c is a constant.
logxy=logc
xy=c

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