Question

# The solution of differential equation coty dx=x dy is ______ .

Solution

## Given differential equation is  coty dx=x dy ⇒1x dx=tany dy On integrating both sides, we get ⇒∫1x dx=∫tany dy⇒log(x)=log(secy)+logC⇒log(xsecy)=logC⇒xsecy=C⇒x=Csecy

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