The solution of differential equation x2 d y-yx-y d x-0 when x-1- y-1 is-

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Ordinary Differential Equations

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Question

The solution of differential equation x²dy + y(x + y)dx = 0 when x = 1, y = 1 is:

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Similar questions

x^{2} d y + y (x + y) d x = 0

y = 1

x = 1

x^{2} d y + y (x + y) d x = 0

x^{2} d y + y (x + y) d x = 0

y = y (x)

x^{2} d y + (y - \frac{1}{x}) d x = 0; x > 0,

y (1) = 1,

y (\frac{1}{2})

Find the particular solution of the differential equation $x^{2} d y = (2 x y + y^{2}) d x,$ given that y= 1 when x = 1.

Find the particular solution of the differential equation $(1 + x^{2}) \frac{d y}{d x} = (e^{m t a n^{- 1} x} - y),$ given that y =1 when x = 0.

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