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Question

The solution of dydx+ytanx=0 is:

A
y=acosx
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B
y=asinx
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C
y=logcosx+c
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D
y=atanx+c
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Solution

The correct option is B y=acosx
dydx+y tan x=0
dyy=tan x dx+c
log y=log c cos x
y=c cos x

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