The solution of -x4-16-x2-4 is x-0-

The correct option is B 16 x = 0 is not a solution as √(16) ≠ 4. Hence the given statement is false. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Surds

The solution ...

Question

The solution of $\sqrt{x^{4} + 16} = x^{2} - 4$ is $x = 0$ .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

The solution of $\sqrt{x^{4} + 16}$ = $x^{2}$ – 4 is

lim x \to \infty [x \sqrt{x^{2} + 4} - \sqrt{x^{4} + 16}]

\frac{(x^{2} + 2) (\sqrt{x^{2} - 16})}{(x^{4} + 2) (x^{2} - 9)} \leq 0

\frac{x^{2} - 4}{x^{2} - 16} \leq 0

x^{6} - x^{5} + x^{4} - x^{2} + x - 1 = 0

x ϵ 0

Join BYJU'S Learning Program