CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The solution of the differential equation dydx+2yx=0 with y(1) = 1 is given by
(a) y=1x2

(b) x=1y2

(c) x=1y

(d) y=1x

Open in App
Solution

(a) y=1x2

We have,

dydx+2y x=0dydx=-2y x12×1ydy=-1 xdxIntegrating both sides, we get121ydy=-1 xdx12log y=-log x+log Clog y12+log x=log Clogyx=log Cyx=C .....1As1 satisfies y1=1, we get1=CPutting the value of C in 1, we getyx=1y=1x2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Angle between Two Planes
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon