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Question

The solution of the differential equation dydx=yx+ϕ(yx)ϕ(yx) is

A
ϕ(yx)=kx
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B
xϕ(yx)=k
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C
ϕ(yx)=ky
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D
yϕ(yx)=k
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Solution

The correct option is A ϕ(yx)=kx

dydx=yx+ϕ(yx)ϕ(yx). Put y=vxdydx=v+xdvdx
The given differential equation becomes
v+xdvdx=v+ϕ(v)ϕ(v) ϕ(v)ϕ(v)dv=dxxlogϕ(v)=log x+log kϕ(v)=kxϕ(yx)=kx

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