The solution of the differential equation dydx=yx+ϕ(yx)ϕ(yx) is
A
ϕ(yx)=kx
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B
xϕ(yx)=k
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C
ϕ(yx)=ky
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D
yϕ(yx)=k
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Solution
The correct option is Aϕ(yx)=kx
dydx=yx+ϕ(yx)ϕ′(yx). Put y=vx⇒dydx=v+xdvdx ∴ The given differential equation becomes v+xdvdx=v+ϕ(v)ϕ′(v)⇒ϕ′(v)ϕ(v)dv=dxx⇒logϕ(v)=logx+logk⇒ϕ(v)=kx⇒ϕ(yx)=kx