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Question

The solution of x2dydx=4y2 is:

A
sin1(y2)+1x=c
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B
x33+sin1(y4)=c
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C
sin1(y2)+2x=c
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D
4y2+2x=c
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Solution

The correct option is D sin1(y2)+1x=c
dy4y2=dxx2
dy4y2=dxx2+c
sin1(y/2)= 1/x+c
sin1(y2)+1/x=c

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