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Question

The solution of (x+2y3)(dydx)=y is (where c is arbitrary constant)

A
x=y3+cy
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B
x=y3cy
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C
y=y3cy
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D
y=y3+cy
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Solution

The correct options are
A x=y3+cy
B x=y3cy
dxdy1yx=2y2
This is linear equation taking y as independent variable.
Here, I.F. =e1ydy=elogy=1y
solution is x 1y=1y2y2dy+c
xy=y2+cx=y3+cy

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