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Question

The solution set of $$x^{2}+13=4x$$ is


A
[3+2i,32i]
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B
[2+3i,23i]
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C
[3i3i]
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D
none of these
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Solution

The correct option is B $$[2+3i,2-3i]$$
$$x^{2}+13=4x\Rightarrow x^{2}-4x+13=0$$
$$\therefore x=\dfrac{4\pm\sqrt{16-52}}{2}=\dfrac{4\pm\sqrt{-36}}{2}=\dfrac{4\pm 6i}{2}=(2\pm 3i)$$
$$\therefore$$ Solution set $$=[2+3i,2-3i]$$

Mathematics

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