The solution set of $x^{2} + 13 = 4 x$ is

[3 + 2 i, 3 - 2 i]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[2 + 3 i, 2 - 3 i]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[3 i - 3 i]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n o n e o f t h e s e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $[2 + 3 i, 2 - 3 i]$
$x^{2} + 13 = 4 x \Rightarrow x^{2} - 4 x + 13 = 0$
$∴ x = \frac{4 \pm \sqrt{16 - 52}}{2} = \frac{4 \pm \sqrt{- 36}}{2} = \frac{4 \pm 6 i}{2} = (2 \pm 3 i)$
$∴$ Solution set $= [2 + 3 i, 2 - 3 i]$

Suggest Corrections

Similar questions

z = ∣ ∣ ∣ ∣ \begin{matrix} 3 + 3 i & 5 - i & 7 - 3 i i & 2 i & - 3 i 3 - 2 i & 5 + i & 7 + 3 i \end{matrix} ∣ ∣ ∣ ∣

\frac{(3 - 2 i) (2 + 3 i)}{(1 + 2 i) (2 - i)} .

If (i, j)th element of matrix A is 2+3i , what is the corresponding element in A* or conjugate of A.

A + i B

\frac{1 + 2 i + 3 i^{2}}{1 - 2 i + 3 i^{2}}

The conjugate of the complex number $\frac{(2 + 3 i)}{4 i}$ is _____.

Join BYJU'S Learning Program