CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The sound intensity level at a point 4m from the point source is 10dB, then the sound level at a distance 2m from the same source will be :

A
26dB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
16dB
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
23dB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
32dB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 16dB
Sound level at A is oB
If the intensity of sound at A 4 cm away from the source is IA
then.
o=10logIAIo Where Io=1012w m2
=logIA1012
IA1012=10
IA=1011wm2
If the source (s) is emmitting the sound energy of power P
IA=P4×(4)2
P=1011×64π w
Intensity of sound (IB) ar point B,2 m
IB=P4π(2)2
IB=64π×101116π10 m2
IB=4×1011 wm2
Sound level at 2m=10log(IBI)
=10log(4×10111012)
=10log40
=16.02
Hence Sound level at 2m from sourceis 16 dB

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Adaptive Q3
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon