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Question

# The space between two plates of a condenser is filled with two dielectric media of thickness t1 and t2 and dielectric constant k1 and k2 respectively. The capacity of the condenser is given by?

A
ϵ0A{K1t1+K2t2}
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B
C=(K1+K2)ε0A/(t1k1+t2k2)
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C
C=ε0A/[(t1/K1)+(t2/k2)]
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D
(K1K2)ε0A(k1+K2)(t1+t2)
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Solution

## The correct option is A ϵ0A{K1t1+K2t2} We know that the capacitance of the dielectric medium, when introduced between capacitor, is given by C=KE0Ad where A is the cross-sectional area, d is the thickness and k is the dielectric constant.Now Capacity of 1st medium C1=K1E0At1 and Capacity of 2nd mediumC2=K2E0At2Now as the dielectric medium are connected in series thus the total capacity is given as C1+C2==K1E0At1+K2E0At2=E0A{K1t1+K2t2}

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