The speed range ratio of a machine tool is (where the symbols used have their usual meanings)
A
Dmax×VminDmin×Vmax
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B
Dmax×VmaxDmin×Vmin
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C
Dmin×VmaxDmax×Vmin
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D
none
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Solution
The correct option is BDmax×VmaxDmin×Vmin The extreme spindle speeds of a machine tool main gearbox, nmax can be determined by nmax=1000VmaxπDmin,nmin=1000VminπDmax
The speed range Rn becomes, Rn=nmaxnmin=Vmax.DmaxVmin.Dmin