Question

The square root of $121x^4{y}^8{z}^6(l-m{)}^2$ is.

• A. $11x^2{y}^4{z}^4|l-m|$
• B. $11x^4{y}^4|l-m|$
• C. $11x^2{y}^4{z}^6|z^3(l-m)|$
• D. $11x^2{y}^4{z}^3|(l-m)|$

Answer 1

The correct option is D $11x^2{y}^4{z}^3|(l-m)|$

$\sqrt{121x^4{y}^8{z}^6(1-m{)}^2}$

$l-m$ may be $-ve$

Therefore it will get out with Mod

$=\sqrt{(11x^2{y}^4{z}^3|l-m|{)}^2}$

$=11x^2{y}^4{z}^3|l-m|$