The stability of $M e_{2} C = C H_{2}$ is more than that of $M e C H_{2} C H = C H_{2}$ due to:

inductive effect of the

M e

groups

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resonance effect of the

M e

groups

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hyperconjugative effect of the

M e

groups

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resonance as well as inductive effect of the

M e

groups

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Solution

The correct option is A hyperconjugative effect of the $M e$ groups
In ${M e}_{2} C = C H_{2}$ , with respect to Alkene the number of
α-Hydrogen atoms are 6 (i.e. the number of hydrogen atoms taking part in hyperconjugation).
While in $M e C H_{2} C H = C H_{2}$ , the number of α-Hydrogen atoms are 2.
So, the extent of hyperconjugation is more in ${M e}_{2} C = C H_{2}$ than in $M e C H_{2} C H = C H_{2}$ .
Thus, ${M e}_{2} C = C H_{2}$ is more stable than $M e C H_{2} C H = C H_{2}$ .
So, the correct answer is option $C$ .

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Similar questions

The stability of $M e_{2} C = C H_{2}$ is more than that of $M e C H_{2} C H = C H_{2}$ due to:

The stability of (CH₃)₂C=CH₂ is more than that of CH₃CH₂CH=CH₂ due to

C H_{2}

M e O - C H_{2}

{M e}_{3} ¨ ⊖ C

¨ ⊖ C H_{3}

M e

{M e}_{3} ¨ ⊖ C

¨ ⊖ C H_{3}

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