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Question

The standard e.m.f. of a cell involving one electron change is found to 0.591 V at 25$$^o$$C. The equilibrium constant of the reaction is:


A
1030
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B
105
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C
1010
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D
101
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Solution

The correct option is C $$10^{10}$$
According to Nernst equation,
$$E=E^o-0.0591log(Q/n)$$,
At eqm, $$E=0$$
$$\displaystyle E^o_{cell} = \frac{0.0591}{n} log K_c$$
$$\therefore 0.591 = \displaystyle \frac{0.0591}{1} log  K_c$$
$$K_c  =10^{10}$$

Chemistry

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