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Question

The standard electrode potential $$(E^{\circ})$$ for Daniel cell is $$+1.1\ V$$. Calculate $$\Delta G^{\circ}$$ for the reaction.
$$Zn(s) + Cu_{(aq)}^{2+} \rightarrow Zn_{(aq)}^{2+} + Cu(s)$$
$$(1\ F = 96500\ C/mol)$$


Solution

$$\Delta G =-nFE$$
$$= -2\times 96500\times 2.2$$ 
=$$-212300\ J$$
=$$-212.3\ kJ$$

Chemistry

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