Question

# The standard electrode potential $$(E^{\circ})$$ for Daniel cell is $$+1.1\ V$$. Calculate $$\Delta G^{\circ}$$ for the reaction.$$Zn(s) + Cu_{(aq)}^{2+} \rightarrow Zn_{(aq)}^{2+} + Cu(s)$$$$(1\ F = 96500\ C/mol)$$

Solution

## $$\Delta G =-nFE$$$$= -2\times 96500\times 2.2$$ =$$-212300\ J$$=$$-212.3\ kJ$$Chemistry

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